Botswana General Certificate of Secondary EducationLive bank

Mathematics — BGCSE

No four-digit code: BGCSE subjects are identified by name, so check your entry with your school and the BEC timetable. Shares the maths topic spine with the IGCSE subject, so the same practice set serves both.

BGCSE subjects carry no four-digit code · no verification date claimed yet · 12 questions available on this subject's topics (25 marks)

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Practice available now (12 questions)

Work out 2/3 + 3/4 − 1/6, giving your answer as a fraction in its lowest terms.

3 marks · Work out · Order of operations, fractions, standard form

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Answer: 5/4 (that is 1¼)

  1. Convert to a common denominator of 12: 8/12 + 9/12 − 2/12
  2. Add and subtract the numerators: 15/12
  3. Cancel to lowest terms: 5/4

Three fractions in one line is a denominator question, not a fraction question. Find the lowest common multiple once, convert once, then work in a single line so a slip costs one mark instead of three.

Write 0.00042 in standard form.

1 mark · Write · Order of operations, fractions, standard form

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Answer: 4.2 × 10⁻⁴

  1. Move the point four places to get 4.2
  2. Smaller than one, so the index is negative

Two things are marked here: the number in front must be between 1 and 10, and the index sign follows the direction you moved the point.

A bakery spends P4,800 a year on fuel. The cost rises by 6% in the first year, and the new amount rises by a further 4% in the second year. Work out the fuel cost after two years.

3 marks · Work out · Percentage change, including repeated change over time

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Answer: P5,291.52

  1. Year one: 4800 × 1.06 = 5088
  2. Year two: 5088 × 1.04 = 5291.52
  3. Money to two decimal places: P5,291.52

Two separate percentage rises never add up to 10%. Use a multiplier for each year and keep every digit until the final rounding.

Solve the simultaneous equations: 3x + 2y = 16 and x − y = 2, showing your method.

3 marks · Solve · Linear and simultaneous equations

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Answer: x = 4, y = 2

  1. From the second equation: x = y + 2
  2. Substitute: 3(y + 2) + 2y = 16
  3. Expand: 5y + 6 = 16, so y = 2 and x = 4

Substitution is quicker than elimination when one equation already says x = something. Marks are given for the substitution step, so write it before you solve.

The nth term of a sequence is 4n − 3. (a) Find the 20th term. (b) Is 100 a term of this sequence? Show how you decide.

3 marks · Find / decide · Sequences and the nth term

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Answer: (a) 77 (b) No, because 4n − 3 = 100 gives n = 25.75, and n must be a whole number.

  1. (a) 4 × 20 − 3 = 77
  2. (b) Set 4n − 3 = 100
  3. Solving: n = 25.75, which is not a whole number, so 100 is not in the sequence

Part (b) is an analysis mark, not a guess. Say what you solved and what the non-integer result means — the meaning is the mark.

In triangle ABC, angle A = 2x, angle B = 3x and angle C = 4x. Find the value of x and the size of the largest angle.

3 marks · Find · Angles, polygons and parallel lines

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Answer: x = 20°, largest angle = 80°

  1. Angles in a triangle total 180°: 2x + 3x + 4x = 180
  2. 9x = 180, so x = 20
  3. Largest angle = 4 × 20 = 80°

Two marks are given here even if the arithmetic slips, provided the equation is right. Write the equation, then solve it.

A rectangle measures 9 cm by 12 cm. Work out the length of a diagonal.

1 mark · Work out · Pythagoras and right-angled trigonometry

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Answer: 15 cm

  1. Pythagoras: diagonal² = 9² + 12²
  2. = 225
  3. Diagonal = 15 cm

The 9-12-15 triangle is a scaled 3-4-5, which appears in papers again and again. Recognising it saves a minute you can spend on a harder question.

A tuck shop records bags of crisps sold each day: 0–4 bags on 6 days, 5–9 on 12 days, 10–14 on 8 days and 15–19 on 4 days. Estimate the mean number of bags sold per day.

4 marks · Estimate · Averages from lists and frequency tables

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Answer: 8.67 bags (2 d.p.)

  1. Midpoints: 2, 7, 12, 17
  2. fx column: 12, 84, 96, 68 → total 260
  3. Frequency total: 30 days
  4. Mean = 260 ÷ 30 = 8.67

The midpoints are estimated, so the answer is an estimate — say so if asked to comment. The fx column is not optional: the division is a marked step, and two marks belong to it.

A fair six-sided dice is rolled twice. What is the probability of rolling a six both times?

1 mark · Find · Probability, with and without replacement

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Answer: 1/36

  1. Independent events multiply
  2. P(6) × P(6) = 1/6 × 1/6 = 1/36

Ask whether the two events are joined by "and" or "or". And multiplies; or adds, after you check nothing overlaps.

Expand and simplify (2x − 3)(x + 5).

1 mark · Expand and simplify · Simplifying, expanding and factorising

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Answer: 2x² + 7x − 15

  1. Four products: 2x·x, 2x·5, −3·x, −3·5
  2. 2x² + 10x − 3x − 15
  3. Collect: 2x² + 7x − 15

Write all four products before collecting. Skipping a term is the single most common error in this question type, and it costs the whole mark rather than part of it.

Find the nth term of the sequence 5, 8, 11, 14, …

1 mark · Find · Sequences and the nth term

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Answer: 3n + 2

  1. Common difference = 3, so the rule starts 3n
  2. n = 1 gives 3, but the first term is 5, so add 2

One mark, five seconds of checking: substitute n = 1 and n = 2 into your own rule. It is the cheapest verification in the whole paper.

Find the median of 4, 7, 2, 9, 5, 7, 3.

1 mark · Find · Averages from lists and frequency tables

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Answer: 5

  1. Order the list: 2, 3, 4, 5, 7, 7, 9
  2. Seven values, so the median is the 4th
  3. Median = 5

Order first, always. With an even count, take the mean of the two middle values — that is where 5.5 style answers come from.