Botswana General Certificate of Secondary EducationLive bank

Biology — BGCSE

No four-digit code: BGCSE subjects are identified by name, so check your entry with your school and the BEC timetable. Shares the biology spine with the IGCSE subject, including the local ecology examples.

BGCSE subjects carry no four-digit code · no verification date claimed yet · 10 questions available on this subject's topics (28 marks)

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Practice available now (10 questions)

A cell is 0.05 mm long. In a photograph it appears as 25 mm long. Calculate the magnification of the photograph.

2 marks · Calculate · Cells, microscopy and organisation

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Answer: ×500

  1. Magnification = image size ÷ actual size
  2. = 25 ÷ 0.05
  3. = ×500

Both lengths must be in the same unit before dividing — here they already are. Convert first, then divide, then write the × sign with no unit.

A digestive enzyme works fastest at 37 °C. Explain why its activity falls sharply at 60 °C.

3 marks · Explain · Enzymes, digestion and absorption

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Answer: The high temperature changes the shape of the enzyme active site (denaturation), so the substrate is no longer complementary and fewer enzyme–substrate complexes form.

  1. Heat changes the shape of the active site
  2. The substrate no longer fits (the enzyme is denatured)
  3. Fewer enzyme–substrate complexes form, so the rate falls

Denaturation is a shape answer. Writing "the enzyme is killed" is a common phrasing and it is wrong: enzymes are molecules, not organisms.

Write the word equation for anaerobic respiration in human muscle.

2 marks · Write · Respiration, aerobic and anaerobic

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Answer: glucose → lactic acid (energy released)

  1. Reactant: glucose
  2. Product: lactic acid, with energy released

"Energy is made" is not acceptable — energy is released, not manufactured. Small wording, real mark.

Two parents are both carriers of a recessive condition (genotype Bb). State the expected ratio of unaffected to affected children, and explain your reasoning.

3 marks · State · Genetics, inheritance and variation

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Answer: 3 unaffected : 1 affected (genotypes 1 BB : 2 Bb : 1 bb)

  1. Gametes from each parent: B and b
  2. Cross: BB, Bb, Bb, bb
  3. Three have at least one B, so three are unaffected; one is bb and affected

Draw the cross. A correct 3:1 with no visible gametes and no square is usually awarded fewer marks than the same answer with the working shown.

State two practical measures a settlement can take to reduce the spread of a water-borne disease such as cholera, and explain how each measure works.

3 marks · State and explain · Microorganisms, disease and prevention

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Answer: Boil or treat the drinking water (kills the bacteria); wash hands with soap (removes bacteria from hands before food is handled); separate the washing area from the drinking point (removes the source of contamination).

  1. Measure one with mechanism, e.g. boiling kills bacteria
  2. Measure two with mechanism, e.g. soap physically removes bacteria
  3. Both must be specific — "be careful" is not a measure

The instruction "and explain how each works" means two marks per point: one for the measure, one for the mechanism. Two measures with no mechanism earns half.

Figure 1 describes a cross-section of a leaf: an upper layer of tightly packed cells containing many chloroplasts; a lower layer of loosely packed cells with air gaps; a waxy layer across the top surface; and small openings on the lower surface, each bordered by two curved cells.

4 marks · Describe · Transport in plants and water relations

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Answer: Palisade layer: packed with chloroplasts for photosynthesis. Spongy layer: air gaps allow gas movement. Waxy cuticle: reduces water loss. Stomata with guard cells: allow carbon dioxide in and control water loss.

  1. Names the upper palisade layer and its role in photosynthesis (1 mark)
  2. Names the spongy layer and explains that the air gaps let gases diffuse (1 mark)
  3. Names the waxy cuticle and states that it reduces water loss (1 mark)
  4. Names the stomata or guard cells and states that they allow gas exchange and control water loss (1 mark)

Describe means say what is there and what it does, in the order the figure presents it. Candidates lose marks by describing the whole leaf from memory instead of answering the figure in front of them.

Which structure is present in a plant cell but not in an animal cell?

1 mark · State · Cells, microscopy and organisation

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Answer: Chloroplast

  1. Chloroplasts are the site of photosynthesis
  2. Animal cells do not photosynthesise
  3. So chloroplasts are plant-only

Watch the wording: cell wall is plant-only, but cell membrane is not. Questions like this are testing whether you read the word.

In an experiment, amylase digests 0.80 g of starch in 2.0 minutes. Calculate the rate of reaction in g per minute.

2 marks · Calculate · Enzymes, digestion and absorption

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Answer: 0.40 g/min

  1. Rate = amount ÷ time
  2. = 0.80 ÷ 2.0
  3. = 0.40 g/min

Rates always carry two units — grams and minutes. A bare 0.40 loses the unit mark, and it is the easiest mark on the question.

A farmer ploughs a field and leaves the bare soil exposed for three weeks before planting. Compare the soil conditions on the ploughed field with those under the undisturbed grassland beside it, and explain why the ploughed field loses more topsoil.

4 marks · Compare · Ecology, food chains and energy transfer

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Answer: Ploughed soil is loose, has little plant cover and dries out; the grassland has roots binding particles and a litter layer. Loose bare soil is lifted by wind and washed by rain, so both wind and water erosion remove more topsoil.

  1. Ploughed soil is loose with no plant cover; grassland soil is bound by roots (1 mark)
  2. Bare soil dries and its particles are easily moved; litter and roots hold moisture and particles (1 mark)
  3. Names a mechanism: wind lifting loose particles, or rain washing them downhill (1 mark)
  4. Links the mechanism to the removal of the nutrient-rich topsoil (1 mark)

In compare questions, keep the two sides in the same sentence. A structure of "Field: ... Grassland: ..." repeated beats a long paragraph about one and a short afterthought about the other.

Figure 2 describes four features of a root hair cell: a long, thin extension of the cell surface; a large permanent vacuole filling much of the cell; no chloroplasts; and many mitochondria.

4 marks · Annotate / Label · Cells, microscopy and organisation

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Answer: Root hair (extension) — increases surface area for water uptake. Large permanent vacuole — stores cell sap and keeps the cell rigid. No chloroplasts — the cell is underground, in darkness, so photosynthesis cannot occur. Many mitochondria — release energy for active transport of mineral ions.

  1. Names the root hair extension and gives its function: surface area for absorption (1 mark)
  2. Names the permanent vacuole and gives its function: stores sap, helps keep the cell firm (1 mark)
  3. States that chloroplasts are absent and links it to the absence of light underground (1 mark)
  4. Names the mitochondria and links the number to active transport and energy release (1 mark)

Label questions are the cheapest marks on the paper and the most commonly rushed. Draw the line, name the part, then add its job in three or four words — the job is usually the mark you are actually being tested on.